JIPMAT Profit & Loss PYQs

2 solved Profit & Loss previous year questions (PYQs) from JIPMAT past year papers — attempt each and check the answer.

Q1:jipmat 2025QA › Profit & LossMediumQA · MCQ

Selling price of a glass is Rs.1,965 and loss percent is 25%. If its selling price is Rs.3,013, then what will be profit percent?

A13%
B10.40%
C15%
D20%

Pick an option to attempt

The Setup: They fumbled the bag on the first sale and took an L (loss). We need to reverse-engineer the original Cost Price (CP) and then calculate the stonks (profit) on the new Selling Price (SP). Step 1: Find the Cost Price. A

25\%

loss means the SP is

75\%

of the CP (

0.75 \times \text{CP}

1965=0.75 \times \text{CP}

\text{CP}=\frac{1965}{0.75}=\frac{1965}{3/4}

\text{CP}=1965 \times \frac{4}{3}=655 \times 4=2620

Step 2: Calculate the new profit. The new SP is

Rs.3013

\text{Profit}=\text{SP}-\text{CP}=3013-2620=393

Step 3: Convert that profit into a percentage.

\text{Profit \%}=\frac{\text{Profit}}{\text{CP}} \times 100

\text{Profit \%}=\frac{393}{2620} \times 100

Cancel a zero:

\frac{393}{262} \times 10

. Notice that

262 \times 1.5=393

\text{Profit \%}=1.5 \times 10=15\%

Final Answer: 15%

Q2:jipmat 2025QA › Profit & LossMediumQA · MCQ

Cost price of article A is Rs.200 more than the cost price of article B. Article A was sold at 10% loss and article B was sold at 25% profit. If the overall profit earned after selling both the articles is 4%, then what is the cost price of article B?

A₹300
B₹400
C₹450
D₹500

Pick an option to attempt

The Setup: This is a balancing act of stonks and Ls. We can set up an algebraic equation representing the net profit across both items to zero in on B's cost price. Let the cost price of B be

x

. That makes the cost price of A equal to

x+200

. Step 1: Express the profit/loss on each individual item. Profit on B

=+25\%

x=0.25x

. Loss on A

=-10\%

(x+200)=-0.10(x+200)=-0.10x-20

. Step 2: Combine them to find the net monetary profit.

\text{Net Profit}=0.25x-0.10x-20=0.15x-20

Step 3: Set up the overall percentage equation. The total cost price of everything is

x+(x+200)=2x+200

. The problem states the overall profit is

4\%

on the total cost. Overall Profit

=0.04(2x+200)=0.08x+8

. Step 4: Equate the two profit expressions and solve for

x

0.15x-20=0.08x+8

Subtract

0.08x

from both sides:

0.07x-20=8

0.07x=28

x=\frac{28}{0.07}=\frac{2800}{7}=400

So, the cost price of article B is Rs.400. Final Answer: 400

JIPMAT Profit & Loss — PYPs

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