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Past Year Questions › JIPMAT › LRDI › Bar Graphs

JIPMAT Bar Graphs — PYPs

3 solved Bar Graphs previous year questions (PYQs) from JIPMAT past year papers — attempt each and check the answer.

Free SolutionsNo Login3 Questions
Q1:jipmat 2025LRDI › Bar GraphsMediumLR · MCQ

Total number of students who appeared and qualified from various cities at a Management Entrance Exam:

The average number of students who qualified in the examination from Kolkata and Delhi is what percent of the average number of students who appeared for the exam from the same cities? (rounded off to 2 digits after the decimal)

question figure
  • A58.61
  • B62.58
  • C73.91
  • D77.96
Pick an option to attempt

Read the two cities off the chart: Kolkata had 32503250 appear and 22502250 qualify; Delhi had 25002500 appear and 20002000 qualify.

Average qualified =2250+20002=42502=2125=\frac{2250+2000}{2}=\frac{4250}{2}=2125.

Average appeared =3250+25002=57502=2875=\frac{3250+2500}{2}=\frac{5750}{2}=2875.

'A is what percent of B' means AB×100\frac{A}{B}\times100, so the answer is 21252875×100=73.9130…\frac{2125}{2875}\times100=73.9130\ldots

The third decimal digit is 33, so rounding to two places gives 73.91% - Option 3.

Q2:jipmat 2025LRDI › Bar GraphsMediumLR · MCQ

Total number of students who appeared and qualified from various cities at a Management Entrance Exam:

What is the difference between the average number of students who appeared in the entrance exam from all the given cities and the average number of students who qualified from all the cities together?

question figure
  • A950
  • B990
  • C1100
  • D1020
Pick an option to attempt

Both averages are over the same five cities, so read each series off the chart and divide by 55.

Appeared: 3000+2250+3250+2500+30005=140005=2800\frac{3000+2250+3250+2500+3000}{5}=\frac{14000}{5}=2800.

Qualified: 1750+1250+2250+2000+20005=92505=1850\frac{1750+1250+2250+2000+2000}{5}=\frac{9250}{5}=1850.

Difference =2800−1850=∗∗950∗∗=2800-1850=**950** - Option 1.

Shortcut: since both are divided by the same 55, you can subtract the totals first - 14000−92505=47505=950\frac{14000-9250}{5}=\frac{4750}{5}=950.

Q3:jipmat 2025LRDI › Bar GraphsEasyLR · MCQ

Total number of students who appeared and qualified from various cities at a Management Entrance Exam:

The number of students who appeared for the exam from Delhi is approximately what percent of the total number of students who appeared for the exam from all the cities together?

question figure
  • A24%
  • B18%
  • C28%
  • D12%
Pick an option to attempt

From the chart, 25002500 students appeared from Delhi.

Across all five cities, 3000+2250+3250+2500+3000=140003000+2250+3250+2500+3000=14000 appeared.

Required percentage =250014000×100=17.857…%=\frac{2500}{14000}\times100=17.857\ldots\%, which is approximately 18% - Option 2.

The other options are far off: 24%24\% would need about 33603360 students and 12%12\% only 16801680.

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