JIPMAT Averages PYQs

2 solved Averages previous year questions (PYQs) from JIPMAT past year papers — attempt each and check the answer.

Q1:jipmat 2025QA › AveragesMediumQA · MCQ

A car owner buys petrol at the rate Rs.17, Rs.19 and Rs.20 per litre, respectively for three consecutive years. Compute the average cost per litre, if he spends Rs.6,460 per year for the three consecutive years.

A18.49
B18.58
C19.20
D21.66

Pick an option to attempt

The Setup: Gas prices are doing us dirty, and taking a simple arithmetic mean of the prices won't work since the money spent is constant, not the volume. We need to find the total money spent and divide it by the total liters of petrol bought to find the true weighted average. Step 1: Calculate the volume of petrol bought each year. Year 1:

\frac{6460}{17}=380

liters. Year 2:

\frac{6460}{19}=340

liters. Year 3:

\frac{6460}{20}=323

liters. Step 2: Calculate total volume and total cash dropped across all three years. Total liters

=380+340+323=1043

liters. Total spent

=6460 \times 3=19380

rupees. Step 3: Find the true average cost per liter.

\text{Average}=\frac{\text{Total Spent}}{\text{Total Liters}}=\frac{19380}{1043}

\text{Average} \approx 18.581

Final Answer: 18.58

Q2:jipmat 2025QA › AveragesMediumQA · MCQ

Let x be median of the data 13, 8, 15, 14, 17, 9, 14, 16, 13, 17, 14, 15, 16, 15, 14. If 8 is replaced by 18, then the median of data is y, then the sum of x and y is equal to:

Pick an option to attempt

The Setup: The median is literally just the middle child of a sorted dataset. We need to sort the raw data to find the first median (

x

), swap a number, re-sort, find the second median (

y

), and add them. Step 1: Count the data points and sort the initial list. There are

15

numbers. The median will be the

(\frac{15+1}{2})^{\text{th}}

term, which is the

8^{\text{th}}

term. Sorted data:

8, 9, 13, 13, 14, 14, 14, \textbf{14}, 15, 15, 15, 16, 16, 17, 17

. The

8^{\text{th}}

term is

14

. So,

x=14

. Step 2: Execute the swap. Replace the

8

with an

18

. The

18

will move to the far right of the sorted list, shifting everything below it down a spot. New sorted data:

9, 13, 13, 14, 14, 14, 14, \textbf{15}, 15, 15, 16, 16, 17, 17, 18

. Step 3: Find the new median (

y

). The

8^{\text{th}}

term is now

15

. So,

y=15

. Step 4: Calculate the final sum.

x+y=14+15=29

Final Answer: 29

JIPMAT Averages — PYPs

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