JIPMAT Coding & Decoding — PYPs

The Setup: We map the replacement operators as stated in the rules.
$(- \Rightarrow \div)$, $(+ \Rightarrow \times)$, $(\div \Rightarrow -)$, and $(\times \Rightarrow +)$. Apply standard BODMAS rules.

Step 1: Test the options
Let's directly decode Option D:
Original: $6\div20\times12+7-1=70$
Substituted: $6 - 20 + 12 \times 7 \div 1$

Step 2: Solve via BODMAS
First, handle division and multiplication:
$12 \times 7 \div 1 = 84$
Equation becomes:
$6 - 20 + 84$

Add and subtract from left to right:
$6 - 20 = -14$
$-14 + 84 = 70$

The logic holds up perfectly. Option D is the mathematically sound equation.

Final Answer: $6\div20\times12+7-1=70$

Step 1: Dox the pattern in the first word
Let's map the letter shifts from ROAST to PQYUR:
* R $\rightarrow$ P ($-2$)
* O $\rightarrow$ Q ($+2$)
* A $\rightarrow$ Y ($-2$, wrapping around the alphabet backward)
* S $\rightarrow$ U ($+2$)
* T $\rightarrow$ R ($-2$)
The hidden mechanic is an alternating shift sequence of $-2$ and $+2$.

Step 2: Apply the mechanic to the target word
Now we run the exact same $-2, +2$ sequence on the word SLOPPY:
* S ($-2$) $\rightarrow$ Q
* L ($+2$) $\rightarrow$ N
* O ($-2$) $\rightarrow$ M
* P ($+2$) $\rightarrow$ R
* P ($-2$) $\rightarrow$ N
* Y ($+2$) $\rightarrow$ A (wrapping past Z)

The final generated string is QNMRNA.

Final Answer: QNMRNA

The Setup: The numbers given are way too small to be based on the alphabetical positional values (A=1, B=2, etc.). The absolute meta strat here is to simply count the number of letters in each word.

Step 1: Dox the hidden mechanic
* DRIVER has 6 letters. $6 \times 2 = 12$.
* PEDESTRIAN has 10 letters. $10 \times 2 = 20$.
* ACCIDENT has 8 letters. $8 \times 2 = 16$.
The rule is completely locked in: count the letters and multiply by 2.

Step 2: Apply to the target
* CAR has exactly 3 letters.
* $3 \times 2 = 6$.

Final Answer: 6