JIPMAT 2025 — LR

All 33 LR previous year questions (PYQs) from the JIPMAT 2025 past year paper, with answers and full solutions.

Q1:jipmat 2025LRDI › Blood RelationsEasyLR · MCQ

Pointing to man in photograph, a woman said, 'His brother's father is the only son of my grandfather'. How is the woman related to the man in the photograph?

• AMother
• BAunt
• CSister
• DGrandmother

Pick an option to attempt

Show solution

The Setup: We break the quote into two bite-sized pieces, decode them independently, and link them back together. Step 1: Decode the first half 'His brother's father'. A man's brother's father is simply his own father. Target = The man's father. Step 2: Decode the second half 'The only son of my grandfather'. If your grandfather has exactly one son, that son is your father. Target = The woman's father. Step 3: Link them together The man's father = The woman's father. If they share the same father, they are siblings. Since the speaker is a woman, she is his sister. Final Answer: Sister

Q2:jipmat 2025LRDI › PuzzlesMediumLR · MCQ

The total number of squares and rectangles in the following figure is:

• A18
• B22
• C20
• D24

Pick an option to attempt

Show solution

Count every square and rectangle the figure contains, not just the obvious ones - the small cells, the larger squares they combine into, and the rectangles formed across the overlapping diamonds. Enumerated one by one, there are 20 in all, each shaded in turn below.

Q6:jipmat 2025LRDI › Logical SequenceMediumLR · MCQ

Match the LIST-I with LIST-II.

• AA-II, B-III, C-IV, D-I
• BA-III, B-II, C-IV, D-I
• CA-IV, B-III, C-II, D-I
• DA-IV, B-III, C-I, D-II

Pick an option to attempt

Show solution

Series A: the four outer numbers multiply, then divide by 10. First figure: $\frac{3\times5\times4\times2}{10}=\frac{120}{10}=12$. Second figure: $\frac{6\times5\times2\times3}{10}=\frac{180}{10}=18$. Applying it to the third: $\frac{2\times5\times2\times9}{10}=\frac{180}{10}=18$. Missing number: 18. Series B: $(\text{top}\times\text{bottom})+(\text{left}\times\text{right})$. First figure: $(2\times5)+(1\times3)=10+3=13$. Third figure: $(3\times4)+(1\times5)=12+5=17$. Applying it to the second: $(4\times6)+(1\times5)=24+5=29$. Missing number: 29. Series C: $(\text{left}-\text{right})\times(\text{top}-\text{bottom})$. First figure: $(15-8)\times(10-8)=7\times2=14$. Second figure: $(9-5)\times(8-6)=4\times2=8$. Applying it to the third: $(11-8)\times(6-4)=3\times2=6$. Missing number: 6. Series D: $(\text{left}\times\text{right})-(\text{top}\times\text{bottom})$. First figure: $(7\times4)-(5\times3)=28-15=13$. Second figure: $(8\times4)-(9\times3)=32-27=5$. Applying it to the third: $(9\times4)-(8\times3)=36-24=12$. Missing number: 12. Matching: A $\to$ 18 $\to$ IV, B $\to$ 29 $\to$ III, C $\to$ 6 $\to$ I, D $\to$ 12 $\to$ II. Hence the correct option is A-IV, B-III, C-I, D-II.

Q7:jipmat 2025LRDI › Dices & CubesEasyLR · MCQ

If four different positions of a dice are shown below, then what number is opposite 3?

• A6
• B4
• C3
• D2

Pick an option to attempt

Show solution

Read off every face that shares a view with 3. The first die shows 3 with 2 and 6, the third shows it with 6 and 1, and the fourth shows it with 5 and 1 - so $2, 6, 1$ and $5$ are all adjacent to 3. That leaves only one number unaccounted for, and a face can only be adjacent or opposite. Hence 4 is opposite 3, which is Option 2.

Q13:jipmat 2025LRDI › Venn DiagramsEasyLR · MCQ

Match the Group in List-I with the Venn diagram in List-II. The List-II diagrams are numbered I to IV, from top to bottom. A. Hospital, Nurse, Patient B. Polygons, Quadrilaterals, Rhombus C. Engine, Piston, Wheel D. Colour, Cloth, Merchant

• AA-I, B-III, C-II, D-IV
• BA-III, B-I, C-II, D-IV
• CA-III, B-IV, C-I, D-II
• DA-III, B-IV, C-II, D-I

Pick an option to attempt

Show solution

A -> III. Nurses and patients are two distinct groups, and both sit inside the larger category 'hospital' - two separate circles enclosed by one big circle. B -> IV. All rhombuses are quadrilaterals and all quadrilaterals are polygons, so the three are fully nested - three concentric circles. C -> I. The engine and the wheel are two separate parts of a car, while the piston is a sub-part of the engine - a circle within a circle, plus one standing apart. D -> II. Colour, cloth and merchant are unrelated as categories: cloth can have a colour and a merchant sells cloth, but none is a subset of another - three separate circles. That gives A-III, B-IV, C-I, D-II, which is Option 3.

Q18:jipmat 2025LRDI › PuzzlesEasyLR · MCQ

The mirror image of the figure is

• A
• B
• C
• D

Pick an option to attempt

Show solution

In a mirror image the left and right sides are swapped, while top and bottom stay put. Options A and B show figures that differ from the original in more than just left-right - the limbs themselves are in different positions - so both are out. Option C is simply the original figure repeated, unchanged, so it cannot be its own mirror image. Option D keeps every limb in the same vertical position but flips the whole figure left to right - the ball moves from the top-left corner to the top-right, and the outstretched arm swaps sides. D is the mirror image. *Tip:* if you're unsure what a mirror image does, elimination gets you there - discard any option that changes the figure itself, and any that repeats the original unchanged.

Q19:jipmat 2025LRDI › Logical SequenceEasyLR · MCQ

Five problem figures are given below. Which of the following figures will continue the same pattern as established by the problem figures?

• A
• B
• C
• D

Pick an option to attempt

Show solution

Each figure holds five arrows - three down the left side, two down the right. Compare the figures in order and only one arrow flips at a time, working through them in reading order: first the left column from top to bottom, then the right column. Figure 1 has every arrow pointing right. Figure 2 flips the top-left, figure 3 the middle-left, figure 4 the bottom-left, and figure 5 the upper-right. That leaves exactly one arrow still pointing right - the bottom-right one. So the next figure in the sequence flips that last arrow, leaving all five pointing left. That is Option 2.

Q22:jipmat 2025LRDI › PuzzlesMediumLR · MCQ

The water image of the figure is

• A
• B
• C
• D

Pick an option to attempt

Show solution

A water image is the figure reflected in the surface below it: top and bottom swap, left and right stay put. It is the opposite of a mirror image, which swaps left and right. Track the landmarks of the original. The short cross-bar sits at the top, the small circle at the bottom-right, one arrowhead points up-left and the other down-right. Invert all of that vertically: the cross-bar drops to the bottom, the circle rises to the top-right - still on the right - and the two arrowheads become down-left and up-right, each keeping its side of the figure. Only Option 3 does this; the others either turn the figure left-to-right or rotate it.

Q24:jipmat 2025LRDI › Venn DiagramsEasyLR · MCQ

In the following diagram, the circle represents businessmen, the square represents dancers, the triangle represents musicians and the rectangle represents Indians. Who among the following is neither a dancer nor a musician, but is a businessman and not an Indian?

• A8
• B11
• C1
• D10

Pick an option to attempt

Show solution

The four conditions pin the region down exactly: businessman means inside the circle; not a dancer means outside the square; not a musician means outside the triangle; not an Indian means outside the rectangle. So we need a region that lies in the circle and in nothing else. Scanning the figure, 10 is the only number sitting inside the circle alone - it falls outside the triangle's right edge, and well clear of both the square and the rectangle. The distractors all fail on the musician condition or the businessman one: 1 and 8 lie inside the triangle only, so both are musicians and neither is a businessman, and 11 lies inside the rectangle only, making it an Indian and not a businessman. Hence the answer is 10, Option 4.

Q27:jipmat 2025LRDI › Bar GraphsMediumLR · MCQ

Total number of students who appeared and qualified from various cities at a Management Entrance Exam: The average number of students who qualified in the examination from Kolkata and Delhi is what percent of the average number of students who appeared for the exam from the same cities? (rounded off to 2 digits after the decimal)

• A58.61
• B62.58
• C73.91
• D77.96

Pick an option to attempt

Show solution

Read the two cities off the chart: Kolkata had $3250$ appear and $2250$ qualify; Delhi had $2500$ appear and $2000$ qualify. Average qualified $=\frac{2250+2000}{2}=\frac{4250}{2}=2125$. Average appeared $=\frac{3250+2500}{2}=\frac{5750}{2}=2875$. 'A is what percent of B' means $\frac{A}{B}\times100$, so the answer is $\frac{2125}{2875}\times100=73.9130\ldots$ The third decimal digit is $3$, so rounding to two places gives 73.91% - Option 3.

Q28:jipmat 2025LRDI › Bar GraphsMediumLR · MCQ

Total number of students who appeared and qualified from various cities at a Management Entrance Exam: What is the difference between the average number of students who appeared in the entrance exam from all the given cities and the average number of students who qualified from all the cities together?

• A950
• B990
• C1100
• D1020

Pick an option to attempt

Show solution

Both averages are over the same five cities, so read each series off the chart and divide by $5$. Appeared: $\frac{3000+2250+3250+2500+3000}{5}=\frac{14000}{5}=2800$. Qualified: $\frac{1750+1250+2250+2000+2000}{5}=\frac{9250}{5}=1850$. Difference $=2800-1850=**950**$ - Option 1. Shortcut: since both are divided by the same $5$, you can subtract the totals first - $\frac{14000-9250}{5}=\frac{4750}{5}=950$.

Q29:jipmat 2025LRDI › Bar GraphsEasyLR · MCQ

Total number of students who appeared and qualified from various cities at a Management Entrance Exam: The number of students who appeared for the exam from Delhi is approximately what percent of the total number of students who appeared for the exam from all the cities together?

• A24%
• B18%
• C28%
• D12%

Pick an option to attempt

Show solution

From the chart, $2500$ students appeared from Delhi. Across all five cities, $3000+2250+3250+2500+3000=14000$ appeared. Required percentage $=\frac{2500}{14000}\times100=17.857\ldots\%$, which is approximately 18% - Option 2. The other options are far off: $24\%$ would need about $3360$ students and $12\%$ only $1680$.

Q30:jipmat 2025LRDI › Pie ChartEasyLR · MCQ

Degree-wise break-up of the expenditure of a family in a month. Total amount spent in a month = Rs.45,800. What is the ratio of the amount spent by the family on medical expenses to the amount spent on groceries?

• A1:2
• B13:21
• C3:5
• D11:23

Pick an option to attempt

Show solution

Each amount is $\frac{\text{sector angle}}{360}\times45800$, so both share the same $\frac{45800}{360}$ factor - and in a ratio that factor cancels. You never need the rupee amounts at all; the sector angles alone give the answer. Medical expenses $=39.6^\circ$ and groceries $=82.8^\circ$, so the ratio is $$\frac{39.6}{82.8}=\frac{396}{828}=\frac{11}{23}$$ (dividing numerator and denominator by $36$). So the ratio is 11 : 23 - Option 4. *Sense check:* $82.8$ is more than double $39.6$, so the ratio must be smaller than $1:2$ - which rules out $1:2$, $3:5$ and $13:21$ immediately.

Q31:jipmat 2025LRDI › Pie ChartEasyLR · MCQ

Degree-wise break-up of the expenditure of a family in a month. Total amount spent in a month = Rs.45,800. What is the total amount spent by the family on Entertainment and Loan EMI together?

• A₹ 9,618
• B₹ 13,282
• C₹ 13,740
• D₹ 11,908

Pick an option to attempt

Show solution

Add the two sector angles first, then convert once - that is one multiplication instead of two. Entertainment $=36^\circ$ and Loan EMI $=68.4^\circ$, together $104.4^\circ$. $$\frac{36+68.4}{360}\times45800=\frac{104.4}{360}\times45800=0.29\times45800=13282$$ So the family spent Rs.13,282 - Option 2. *Sense check:* $104.4^\circ$ is a little under a third of the circle, and a third of $Rs.45,800$ is about $Rs.15,267$ - so an answer just below that is right, which rules out $Rs.9,618$.

Other JIPMAT papers & sections