2 solved Percentages previous year questions (PYQs) from past year papers — attempt each and check the answer.
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Q1:jipmat 2025QA › PercentagesMediumQA · MCQ
Match the LIST-I with LIST-II.
LIST-I
A. 60% of 264
B. 60% of 28% of 240
C. 85% of 485.5
D. 550% of 250
LIST-II
I. 20% of 6875
II. 50% of 825.35
III. 15% of 1056
IV. 8.4% of 480
Choose the correct answer from the options given below:
AA-II, B-IV, C-III, D-I
BA-II, B-III, C-I, D-IV
CA-III, B-IV, C-I, D-II
DA-III, B-IV, C-II, D-I
Pick an option to attempt
Don't evaluate all eight - start with the entry that is quickest to compute and let elimination do the rest.
D is the cleanest: 550%×250=100550×250=55×25=1375. Scanning List-II, I gives 20%×6875=56875=1375. So D-I, which already eliminates Options 2 and 3.
A is the next easy one: 0.6×264=158.4. In List-II, III gives 15%×1056 - split it as 10%=105.6 plus 5%=52.8, total 158.4. So A-III, and that settles it as Option 4.
The remaining two confirm it:
B: 0.6×0.28×240=40.32, matching IV: 0.084×480=40.32.
C: 0.85×485.5=412.675, matching II: 0.5×825.35=412.675.
Hence A-III, B-IV, C-II, D-I - Option 4.
Q2:jipmat 2025QA › PercentagesEasyQA · MCQ
Three numbers A, B and C are such that A is 40% less than B, and C is 40% of the sum of A and B. The difference between A and B is what percentage of C?
A60.50%
B64%
C62.50%
D60%
Pick an option to attempt
The Setup: This is a classic percentage chain. The easiest way to not fumble the bag is to anchor one of the variables to 100 and let the rest fall into place.
Step 1: Let B be the anchor. We set B=100.
A is 40% less than B. So, A=100−40=60.
Step 2: Find the value of C based on A and B.
C is 40% of the sum of A and B.
Sum=60+100=160.
C=0.40×160=64.
Step 3: Find the difference between A and B.
Difference=B−A=100−60=40.
Step 4: Calculate what percentage this difference is of C.
Percentage=CDifference×100Percentage=6440×100
Simplify the fraction by dividing by 8: 85.
Since 81=12.5%, then 85=5×12.5%=62.5%.
Final Answer: 62.50%