If '-' stands for 'division', '+' for 'multiplication', '/' for 'subtraction' and 'x' for 'addition', then which one of the following equations is correct?
A6+20−12÷7−1=38
B6−20÷12×7+1=57
C6+20−12÷7×1=62
D6÷20×12+7−1=70
Pick an option to attempt
The Setup: We map the replacement operators as stated in the rules.
(−⇒÷), (+⇒×), (÷⇒−), and (×⇒+). Apply standard BODMAS rules.
Step 1: Test the options
Let's directly decode Option D:
Original: 6÷20×12+7−1=70
Substituted: 6−20+12×7÷1Step 2: Solve via BODMAS
First, handle division and multiplication:
12×7÷1=84
Equation becomes:
6−20+84
Add and subtract from left to right:
6−20=−14−14+84=70
The logic holds up perfectly. Option D is the mathematically sound equation.
Final Answer:6÷20×12+7−1=70
If ROAST is coded as PQYUR in a certain code language, then how will SLOPPY be coded in that language?
AMRNAQN
BNRMNQA
CQNMRNA
DQANNMR
Pick an option to attempt
Step 1: Dox the pattern in the first word
Let's map the letter shifts from ROAST to PQYUR:
* R → P (−2)
* O → Q (+2)
* A → Y (−2, wrapping around the alphabet backward)
* S → U (+2)
* T → R (−2)
The hidden mechanic is an alternating shift sequence of −2 and +2.
Step 2: Apply the mechanic to the target word
Now we run the exact same −2,+2 sequence on the word SLOPPY:
* S (−2) → Q
* L (+2) → N
* O (−2) → M
* P (+2) → R
* P (−2) → N
* Y (+2) → A (wrapping past Z)
The final generated string is QNMRNA.
Final Answer: QNMRNA
If DRIVER = 12, PEDESTRIAN = 20 and ACCIDENT = 16, then CAR is equal to:
A3
B6
C8
D10
Pick an option to attempt
The Setup: The numbers given are way too small to be based on the alphabetical positional values (A=1, B=2, etc.). The absolute meta strat here is to simply count the number of letters in each word.
Step 1: Dox the hidden mechanic
* DRIVER has 6 letters. 6×2=12.
* PEDESTRIAN has 10 letters. 10×2=20.
* ACCIDENT has 8 letters. 8×2=16.
The rule is completely locked in: count the letters and multiply by 2.
Step 2: Apply to the target
* CAR has exactly 3 letters.
* 3×2=6.
Final Answer: 6